Nursing homes in Seymour, WI
Compare 1 Medicare- and Medicaid-certified nursing home in Seymour, part of the Outagamie area. Average overall CMS Five-Star rating is 4★ — above the national average (3.1★). Ratings are sourced from the latest CMS Care Compare provider extract.
Residents in Seymour, Wisconsin, have access to one nursing home facility serving the 54165 ZIP code area within Outagamie County. Based on the latest CMS Care Compare data, the city maintains an average overall quality rating of 4 out of 5 stars. Good Shepherd Services Ltd currently represents the local community, meeting federal quality benchmarks to provide dedicated skilled nursing care for families throughout this region of Wisconsin.
Rating distribution
avg 4★ · 1 homesWhat to look for in Seymour
- All homes in Seymour score 3★ or higher on compliance — a positive sign on regulatory standards.
- 1 of 1 home meets a 4★+ staffing benchmark — ask about RN coverage at night.
- No 5★ overall homes in this suburb. The strongest performer is GOOD SHEPHERD SERVICES LTD at 4★.
- 0 of 1 homes sit below the national average (3.1★). Use the comparison tool to weigh trade-offs.
All homes in Seymour
| GOOD SHEPHERD SERVICES LTD GOOD SHEPHERD HOME, LTD · Medium · Not for Profit | 4.0 | 4 | 0 | 4 | 4 |
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Each home is scored 1–5★ across compliance, residents' experience, staffing, and quality measures, then combined into an overall rating.